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X^2+2X=3720
We move all terms to the left:
X^2+2X-(3720)=0
a = 1; b = 2; c = -3720;
Δ = b2-4ac
Δ = 22-4·1·(-3720)
Δ = 14884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14884}=122$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-122}{2*1}=\frac{-124}{2} =-62 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+122}{2*1}=\frac{120}{2} =60 $
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